ALL-ZEBRAS
Here are some Zebras to Hunt for !!
Distinct Eigen-Values correspond to linearly independent Eigen-Vectors.(Prove it !!)
If all eigen vectors are linearly independent then the matrix is diagonalizable and the diagonal matrix has \(\lambda_1 , \lambda_2, \cdots \lambda_n\) as diagonal entries.
Let \(a_n = (\ln 3)^n \sum_{k=1}^{n} \frac{k^2}{k!(n-k)!}\) . Then the sum of the series \(a_1 + a_2 + a_3 + ... \to \infty\) , is equal to?
A is a \(n \times m\) matrix and B is a \(m \times n\) matrix . If \(|I_{n} - AB|\) is non-singular so is \(|I_{m} - BA|\)
For each positive integer \(n \ge 3\), define \(A_n\) and \(B_n\) as \(A_n = \sqrt{n^2 + 1} + \sqrt{n^2 + 3} + \cdots + \sqrt{n^2+2n-1}\) , \(B_n = \sqrt{n^2 + 2} + \sqrt{n^2 + 4} + \cdots + \sqrt{n^2 + 2n}.\) Determine all positive integers \(n\ge 3\) for which \(\lfloor A_n \rfloor = \lfloor B_n \rfloor\).